RRB Group D 23-Oct-2018 Shift 3 Solved Paper

Question : 52 of 100

Marks: +1, -0

If Seeta walks from her home to school at a speed of 4 km/h, she is late by 9 min. If she walks at a speed of 6 km/h, she reaches the school 6 min early. What is the distance between her school and her home?

6 km
4 km
7 km
3 km

Validate

Solution:

4={D}/{t+{9}/{60}}

...(1)

6={D}/{t-{6}/{60}}

...(2)
From eq. (1) and (2)

4(t+{9}/{60})=6(t-{6}/{60})

4 t+{4 ×9}/{60}=6 t-{6 ×6}/{60}

2 t={36+36}/{60}={72}/{60}={6}/{5}

t={6}/{10}

hour

D=4(t+{9}/{60})=4({6}/{10}+{9}/{60})

={(36+9)}/{60} ×4

{D}={45}/{15}=3 {km}

Distance

=3 {km}

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