RRB Group D 22-Sep-2018 Shift 1 Solved Paper

Question : 99 of 100

Marks: +1, -0

Pipes

A, B

and

C

are attached to an empty cistern. While the first two can fill the cisternin 6.6 and 16.5 hours respectively, the third can drain the cistern, when filled, in 9.9 hours. If all the three pipes are opened simultaneously when the cistern is three-fifths full, how many hours will be needed to fill the cistern?

3.5
4
3.6
3.75

Validate

Solution:

Tank fill by pipe

{A}, {B}

and

{C}

in one hour

={1}/{6.6}+{1}/{16.5}-{1}/{9.9}={1}/{0.11}

=9.09

(Time to fill the full tank)
Already tank is

{3}/{5}

part is full.
Empty tank

=1-{3}/{5}={2}/{5}

2/ {5}

th of the tank will be fill in

9.09 ×{2}/{5}=3.6

hours

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