RRB Group D 2-Nov-2014 Shift 1 Solved Paper

Question : 77 of 100

Marks: +1, -0

The H.C.F. of 3556 and 3444 is

Solution:

3,556=2^{2} × 7 × 127

3,444=2^{2} × 3 × 7 × 41

{\HCF} \;\text " of "\; 3556 \;\text " and "\; 3444=2^{2} × 7=

28

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