RRB Group D 19-Sep-2018 Shift 1 Solved Paper

Question : 4 of 100

Marks: +1, -0

The sum of the lengths of the edges of a cube is equal to three-fifths of the perimeter of square. If the numerical value of the volume of the cube is equal to the numerical value of the area of the square, then the perimeter of the square is:

500 units
480 units
360 units
300 units

Validate

Solution:

Suppose length of side of cube = a
length of side of square = L

12 a=(4 L) × \;{3}/{5}

{a}=\;{ {L}}/{5}

and

{a}^{3}= {L}^{2}

(\;{ {L}}/{5})^{3}= {L}^{2}

\;{ {L}^{3}}/{125}= {L}^{2} ⇒ {L}=125

Perimeter of square

=4 {L}=4 × 125=500

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