RRB Group D 17-Sep-2018 Shift 2 Solved Paper

Question : 29 of 100

Marks: +1, -0

Raju walks 4 km towards East. Then, he turns left and walks another 3 km .In which direction and at what distance is he from his initial position?

Solution:

according to the question. by Pythagoras theorem,

{AC}^{2}= {BC}^{2}+ {AB}^{2}

A C^{2}=3^{2}+4^{2}

{AC}^{2}=9+16

{AC}=√{25}=5 {Km}

So, Raju is

5 {Km}

far from his initial point and Raju is North-East direction from initial point.

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