{2^{8}-1}/{(\sqrt{2})^{12}}=?

RRB Group D 17-Sep-2018 Shift 1 Solved Paper

Question : 36 of 100

Marks: +1, -0

\;{2^{8}-1}/{(√{2})^{12}}=?

Solution:

\;{2^{8}-1}/{(√{2})^{12}}=\;{2^{8}-1}/{2^{6}}

=2^{2}-\;{1}/{2^{6}}=4-\;{1}/{64}=\;{255}/{64}

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