Choose one of the following options which is equal to: \frac{1+\cos\theta}{\sin\theta}

Correct Answer is : sinθ1−cosθ

\frac{1-2sin^2\theta}{\cos\theta}

\frac{\sin\theta}{1-\cos\theta}

\frac{1+\sin^2\theta}{\sin\theta\,\cos\theta}

\frac{1+2cos\theta}{\sin\theta\,\cos\theta}

RRB Group D 17-Dec-2018 Shift 1 Soled Paper

Question : 99 of 100

Marks: +1, -0

Choose one of the following options which is equal to:

{1+cosθ}/{sinθ}

Solution:

{1+cosθ}/{sinθ}×{1-cosθ}/{1-cosθ}={1-cos^2θ}/{sinθ(1-cosθ)}

={sin^2θ}/{sinθ(1-cosθ)}={sinθ}/{1-cosθ}

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