If \sec \theta+\tan \theta=12.5, then \sec \theta-\tan \theta=?

RRB Group D 15-Sep-2018 Shift 1 Solved Paper

Question : 72 of 100

Marks: +1, -0

\sec θ+\tan θ=12.5,

then

\sec θ-\tan θ=?

Solution:

(\sec θ+\tan θ)(\sec θ-\tan θ)=12.5(\sec θ-\tan θ)

\sec ^{2} θ-\tan ^{2} θ=12.5(\sec θ-\tan θ)

\;{1}/{12.5}=0.08=\sec θ-\tan θ

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