RRB Group D 15-Oct-2018 Shift 1 Solved Paper

Question : 5 of 84

Marks: +1, -0

A smallest 5 -digit number, when divided by 4 , 5 and

7,

leaves a remainder of 3 in each case. The number is:

Solution:

{LCM}

of 4,5 and 7

=2 ×2 ×5 ×7=140

Smallest five digit no

=10,000

=140 ×72+3

=10080+3

=10083

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