RRB Group D 10-Oct-2018 Shift 2 Solved Paper

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Question : 18 of 100

Marks: +1, -0

The work done across two points having a potential difference of

10 {V}

is

30 {J}

. Then the electric charge flowing between the two points is :

3 Coulomb
3 Joule
3 Ampere
$3 {\Ohm}$

Solution:

Work done

={q}×{V}

30={q} ×10

{q}=30 / 10=3

Coulomb

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