RRB Group D 10-Dec-2018 Shift 1 Solved Paper

Question : 83 of 100

Marks: +1, -0

Starting from point O facing West a man walks 4km to reach point A. He turns right, walks 4 km and reaches point B. He then turns right, walks 4km and reaches point C. Then, he turns right walks 3 km and reaches point D. He turns left, walks 4 km and reaches point E. Then, he turns right, walks 5 km and reaches point F. The shortest distance (in km) between point A and point E is :

$5√{65}$
$2√{65}$
$√{68}$
$√{65}$

Validate

Solution:

AE=

√{8^2+1^2}=√{64+1}=√{65}

Go to Question:

Prev Question

Next Question