RRB Group D 10-Dec-2018 Shift 1 Solved Paper

∠CBD= 180-(80°+50°)=50°

∠CBD=∠CED
(Because on same road)
∠CED= 50°
and ∠BEA= 180°-(80°+30°)=70°
∠BEC=180°-(70°+50°)=60°
and ∠BCE=180°-(∠CBE +∠BEC)
=180°-(100°+60°)=20°