RRB Assistant Loco Pilot and Technician Model Paper 6 with solutions

Here, a = 2
d = 4 – 2 = 2
${\mathit{t}}_{\mathit{n}}$ = a + (n – 1)d
⇒ 100 = 2 + (n – 1) × 2
⇒ 100 = 2 + 2n – 2
∴ n = $\frac{100}{2}$ = 50
∴ ${\mathit{S}}_{\mathit{n}}$ = $\frac{\mathit{n}}{2}${2a + (n -1) x d}
${\mathit{S}}_{50}$ = $\frac{50}{2}${2 x 2 + (50 -1) x 2}
= 25(4 + 49 × 2)
= 25 × 102
= 2550.