RRB Assistant Loco Pilot and Technician Model Paper 2 with solutions

Let radius of cone = 5x cm
and height of cone = 12 x cm
volume of cone = $\frac{1}{3}\mathit{\pi }{\left(5\mathit{x}\right)}^2\times 12\mathit{x}$
⇒ $\frac{1}{3}\times \frac{22}{7}\times 25{\mathit{x}}^2$ × 12x = 314
⇒ 3.14 × 100 ${\mathit{x}}^3$ = 314
⇒ 314${\mathit{x}}^3$ = 314
⇒ ${\mathit{x}}^3$ = 1
⇒ x = 1
∴ Radius = 5x = 5 × 1 = 5 cm
height = 12x = 12 × 1 = 12 cm
slant height = $\sqrt{{\left(5\right)}^2+{\left(12\right)}^2}=\sqrt{169}$ = 13 cm