RRB Assistant Loco Pilot and Technician Model Paper 2 with solutions

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Question : 10 of 75

Marks: +1, -0

If secθ =

5/4

, then what will be the value of

{\sec\θ-2\cos\θ}/{\tan\θ-\cot\θ}

$7/12$
$3/5$
$1/12$
$1/7$

Solution:

∵ sec θ =

5/4=h/b

∴ p = 3
cos θ =

b/h=4/5

tan θ =

p/b=3/4

⋅ cot θ =

b/p=4/3

Now,

{\secθ-2\cosθ}/{\tanθ-\cotθ}

=

{5/4-2×4/5}/{3/4-4/3}

=

{{ 5 } /{ 4 } - { 8 }/ { 5 } }/ { { 9 - 16 } /{ 12 } }

=

{ { 25 - 32 }/ { 20 } }/{ - { 7 }/ { 12 } }

= -

{ 7 }/ { 20 }× - { 12 }/ { 7 }

=

{ 12 }/ { 20 } = { 3 } /{ 5 }

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