RRB Assistant Loco Pilot and Technician Model Paper 10 with solutions

ABCD is a square with side 5 cm

BD = AC = diagonal of the square
∴ Area of the square = $\frac{1}{2}{\left(\mathrm{diagonal}\right)}^2={\left(\mathrm{side}\right)}^2$
⇒ $\frac{1}{2}{\left(\mathrm{diagonal}\right)}^2$ = 5 × 5
⇒ diagonal = $\sqrt{50}$
∵ AC = BD = $\sqrt{50}$
∴ OB = $\frac{\sqrt{50}}{2}$
∴ By Pythagorastheorem
OE = Radius = $\frac{5}{2}$
∴ $\frac{\mathrm{Perimeter}\mathrm{of}\mathrm{Square}}{\mathrm{Circumference}\mathrm{of}\mathrm{circle}}$ = $\frac{5\times 4}{2\mathit{\pi }\times \frac{5}{2}}=\frac{4}{\mathit{\pi }}$