Volumes Practice Test 2

Question : 23 of 40

Marks: +1, -0

An agricultural field is in the form of a rectangle of length 20m and width 14m. A pit 6m long, 3m wide and 2.5m deep is dug in a corner of a field and the earth taken out of the pit is spread uniformly over the remaining area of the field. The level of the field has been raised by:

15.16 cm
16.17 cm
17.18 cm
18.19 cm

Validate

Solution:

Area of the agricultural field excluding pit = 20 × 14 – 6 × 3 = 262

m^2

Now, 262 × h = 6 × 3 × 2.5
∴ h =

{6×3×2.5}/{262}

{22.5}/{131}

m =

{2250}/{131}

= 17.18 cm

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