What is the value of \sin^3 60^\circ \cot 30^\circ - 2\sec^2 45^\circ + 3\cos 60^\circ \tan 45^\circ - \tan^2 60^\circ?

Trigonometry Practice Test 2

Question : 18 of 22

Marks: +1, -0

What is the value of

\sin^3 60° \cot 30° - 2\sec^2 45°

+ 3\cos 60° \tan 45° - \tan^2 60°

Solution:

\sin^3 60° \cot 30° - 2\sec^2 45°

+ 3\cos 60° \tan 45° - \tan^2 60°

=(√3/2)^3(√3)-2(√2)^2+3(1/2)(1)-(√3)^2

=9/8-4+3/2-3=-35/8

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