If \cot\theta=\frac{2xy}{x^2-y^2} then what is cos θ equal to?

Trigonometry Practice Test 2

Question : 1 of 22

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\cotθ={2xy}/{x^2-y^2}

then what is cos θ equal to?

Solution:

Given,

\cotθ={2xy}/{x^2-y^2}

In ΔABC,

AC^2=(x^2-y^2)^2+(2xy)^2

⇒AC^2=(x^2+y^2)^2

⇒AC=x^2+y^2

∴\cosθ={AB}/{AC}={2xy}/{x^2+y^2}

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