If 0° < θ < 90° and \cos^2\theta - \sin^2 \theta=1 /2, then what is the value of θ?

Trigonometry Practice Test 1

Question : 6 of 40

Marks: +1, -0

If 0° < θ < 90° and

\cos^2θ - \sin^2 θ=1 /2

, then what is the value of θ?

Solution:

\cos^2 - \sin^2 θ=1 /2

⇒\cos2θ=1/2=\cos 60°

⇒θ=30°

Go to Question:

Prev Question

Next Question