Trigonometry Practice Test 1

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Question : 10 of 40

Marks: +1, -0

The value of

(√3\cosec20°-\sec20°)

is:

2
$2 √3$
4
$√8/ 2$

Solution:

(√3\cosec20°-\sec20°)

=\tan 60°\cosec20°-\sec 20°

={\sin 60°}/{\cos 60°} . 1/{\sin 20°}-1/{\cos 20°}

={\sin 60°\cos 20°-\cos 60°\sin 20°}/{\cos 60° .\sin 20° \cos 20°}

={\sin (60°-20°)}/{1/2 . 1/2 (2\sin 20° \cos 20°)}

=4{\sin 40°}/{\sin 40°}=4

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