Surds and Indices Practice Test 1

Question : 26 of 40

Marks: +1, -0

Find the value of

1/(216)^{-2/3}+1/(256)^{-3/4}+1/{(32)^{-1/5}}

Solution:

1/(216)^{-2/3}+1/(256)^{-3/4}+1/{(32)^{-1/5}}

=(6^3)^{2/3}+(4^4)^{3/4}+(2^5)^{1/5}

=6^2+4^3+2=102

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