Simplification Test 9

Here, Cost of 1 table = Cost of$\frac{5}{2}$ chairs.
Cost of (15 chairs + 2 tables) = Cost of (15 chairs + 2 × $\frac{5}{2}$ chairs) = cost of 20 chairs.
Now cost of (12 chairs + 3 tables) = cost of (12 chairs + 3 × $\frac{5}{2}$ chairs) = cost of $\frac{39}{2}$ chairs
Since, cost of 20 chairs = Rs. 4000
∴ cost of $\frac{39}{2}$ chairs$=\frac{4000}{20}\times \frac{39}{2}$ = Rs. 3900