\frac{(3 2/3)^2-(2 1/2)^2}{(4 3/4)^2-(3 1/3)^2}\div{\frac{3 2/3-2 1/2}{4 3/4-3 1/3}} is simplified to:

Simplification Test 4

Question : 39 of 40

Marks: +1, -0

{(3 2/3)^2-(2 1/2)^2}/{(4 3/4)^2-(3 1/3)^2}÷{{3 2/3-2 1/2}/{4 3/4-3 1/3}}

is simplified to:

Solution:

{a^2-b^2}/{c^2-d^2}÷{{a-b}/{c-d}}

={(a-b)(a+b)}/{(c+d)(c-d)}×(c-d)/(a-b)

={a+b}/{c+d}

Now,

{a+b}/{c+d}={11/3+5/2}/{19/4+10/3}

={{22+15}/6}/{{57+40}/12}

=37/6×12/97=74/97

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