\frac{(2 2/3+3 4/7)^2+(2 2/3-3 4/7)^2}{(8/3)^2+(25/7)^2}=?

Simplification Test 4

Question : 14 of 40

Marks: +1, -0

{(2 2/3+3 4/7)^2+(2 2/3-3 4/7)^2}/{(8/3)^2+(25/7)^2}=?

Solution:

{(2 2/3+3 4/7)^2+(2 2/3-3 4/7)^2}/{(8/3)^2+(25/7)^2}

={(8/3+25/7)^2+(8/3-25/7)^2}/{(8/3)^2+(25/7)^2}

={2[{(8/3)^2+(25/7)^2}]}/{(8/3)^2+(25/7)^2}=2

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