\frac{(.08)^3+(.011)^3}{(.08)^2-.08\times.011+(0.11)^2}=?

Simplification Test 2

Question : 19 of 40

Marks: +1, -0

{(.08)^3+(.011)^3}/{(.08)^2-.08×.011+(0.11)^2}=?

Solution:

{(.08)^3+(.011)^3}/{(.08)^2-.08×.011+(0.11)^2}

={ (0.08+.011)[{(.08)^2-.08×.011+(0.11)^2}]}/{(.08)^2-.08×.011+(0.11)^2}

= .08 + .011 = .091

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