\frac{(13)^3+7^3}{(13)^2+7^2-?}= 20

Simplification Test 1

Question : 17 of 40

Marks: +1, -0

{(13)^3+7^3}/{(13)^2+7^2-?}= 20

Solution:

{(13)^3+7^3}/{(13)^2+7^2-?}= 20

⇒(13)^2+(7)^2-?

={(13)^3+(7)^3}/(13+7)

={(13+7)(13^2+7^2-13×7)}/(13+7)

(Putting, 20 = 13 + 7)
Now,

13^2 + 7^2 - ? = 13^2 + 7^2 - 91

∴ ? = 91

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