Simple Interest Practice Test 3

Let parts of A, B and C are Rs. a, Rs. b and Rs. c respectively; then,
$\mathit{a}+\frac{\mathit{a}\times 4\times 4}{100}$ $=\mathit{b}+\frac{\mathit{b}\times 4\times 5}{100}$ $=\mathit{c}+\frac{\mathit{c}\times 4\times 6}{100}$
$\Rightarrow \frac{29}{25}\mathit{a}=\frac{30}{25}\mathit{b}=\frac{31}{25}\mathit{c}$
Hence, a : b : c = 930 : 899 : 870
Sum of prportionals = 930 + 899 + 870 = 2699
∴ Out of 8097, A's part =$\frac{930}{2699}\times 8097$ = Rs. 2790;
B's part = $\frac{899}{2699}\times 8097$ = Rs. 2697
Hence, it is clear that A's part exceeds B's part by Rs. 2790 – Rs. 2697 = Rs. 93