Simple Interest Practice Test 1

 Given value = Rs 44,000
It is divided into 3 parts but not equal parts
let the 3 parts be x, y, z
⇒ x + y + z = 44,000 _____ (i)
Now interest on all parts is same
⇒ $\mathit{x}\times \frac{6}{100}\times 2$ _____ (ii)
$=\mathit{y}\times \frac{8}{100}\times 3$ ________ (iii)
$=\mathit{z}\times \frac{6}{100}\times 6$ _________(iv)
On solving ii & iii we get
x/z = y (or) x = 2y (or) y = 3/2 z
On solving ii & iv we get
x/3 = z (or) x = 3z
Now put these values in (i)
$\Rightarrow 3\mathit{z}+\frac{3}{2}\mathit{z}+\mathit{z}=44,000$
on solving ,we get
z = 8000
y = 12,000
x = 24,000
so the smallest sum that was lent is Rs 8,000