Sets Practice Test 1

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Question : 15 of 33

Marks: +1, -0

If the sets A and B are defined as

A=\{(x,y):x=1/y^2,y≠0,y∈R\}

B = \{(x, y) : x = -3y, y ∈ R\}

then

A ∩ B = A
A ∩ B = B
A ∩ B = ϕ
A ∩ B = A′
None of these

Solution:

We have

x=1/y^2

...(i)

x=-3y

...(ii)
From (i) and (ii),

1/y^2=-3y

⇒y^3=-1/3

[which does not give any real value of y]
So, A ∩ B = ϕ

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