Ratio and Proportion Practice Test 2

Let the original earnings of Rahul and Dinesh be Rs 9x and 13x.
New earnings of Rahul = 130% of Rs 9x
$=\mathrm{Rs}\left(\frac{130}{100}\times 9\mathit{x}\right)=\mathrm{Rs}\frac{117}{10}\mathit{x}$
New earnings of Dinesh = 85 % of Rs 13x
$=\mathrm{Rs}.\frac{85}{100}\times 13\mathit{x}=\mathrm{Rs}.\frac{221}{20}\mathit{x}$
$\therefore \frac{117}{10}\mathit{x}:\frac{221}{20}\mathit{x}=18:17$
$\Rightarrow \frac{117\mathit{x}\times 20}{221\mathit{x}\times 10}=\frac{18}{17}$
This does not give x. So, the given data is inadequate