Progression Practice Test 1

Question : 22 of 23

Marks: +1, -0

Find the sum of the first 14th term of an AP whose first term is 5 and the common difference is

2 /3

Solution:

Given that a = 5 and

d = 2/3

∴S_14=14/2[2×5+(14-1)2/3]

=392/3

Go to Question:

Prev Question

Next Question