Progression Practice Test 1

Question : 2 of 23

Marks: +1, -0

Find 3rd term from the end of the GP 2, 6, 18, 54 ..... 1,458.

Solution:

We have a = 2 and r = 3 and L = 1,458 then the 3rd term from the end of the series is

=L(1/r)^{n-1}=1458(1/3)^{3-1}

= 162

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