Progression Practice Test 1

Question : 19 of 23

Marks: +1, -0

Find the 31st term of the sequence -11, 33, -99, 297..... .

Solution:

The given sequence is GP with a = -11 and r = -3

∴ t_n = ar^{n-1} = (-11)(-3)^{n-1}

= (-1)^n 11 × 3^{n-1}

T_31 = (-1)^31 11 × 3^{31-1}

T_31 = -11 × 3^30

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