Profit and Loss Practice Test 8

Question : 24 of 40

Marks: +1, -0

The price of an article was increased by p% and then the new price was decreased by p%. If the last price was Rs 100, the original price was:

Solution:

Let price = x
Price of article increased = p%
New price

= x+{px}/100

Decreased percentage of new price = p %
Price

= (x+{px}/100)-(x+{px}/100)p/100

According to the statement,

x+{px}/100-{xp}/100-{p^2x}/10000=100

x-{p^2x}/10000=100

x=\Rs 100/{1-(p^2/100^2)}

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