Profit and Loss Practice Test 6

Let the cost price = 100
Let marked price of goods = x
Discount percentage on the goods = 20%
Now selling price $=\mathit{x}-\frac{20}{100}\times \mathit{x}=\frac{4\mathit{x}}{5}$
Cash discount $=6\frac{1}{4}\%=\frac{25}{4}\%$
New selling price of goods $=\frac{4\mathit{x}}{5}-\frac{4\mathit{x}}{5}\times \frac{25}{4}\times \frac{1}{100}=\frac{3\mathit{x}}{4}$
Sale price = 20% of cost = 100 + 20 = Rs 120
$\frac{3\mathit{x}}{4}=120$
$\mathit{x}=160$
So,$\begin{array}{ccc}\mathrm{CP}& \mathrm{SP}& \mathrm{Marked}\mathrm{price}\\ 100& 120& 160\end{array}$
Cost marked for sale should be $=\frac{60}{100}\times 100=60\%$