Profit and Loss Practice Test 4

Let the original marked price of the fan = x
Discount on fan = 10%
Price of the fan $=\mathit{x}-\frac{10\mathit{x}}{100}=\frac{9\mathit{x}}{10}$
During clearance, discount over alreadydiscounted price $=\frac{9\mathit{x}}{10}-\frac{9\mathit{x}}{10}\times \frac{6}{100}=846$
$\mathit{x}=\mathrm{Rs}1,000$
So, the marked price of the fan is Rs 1,000.