If both 17^2 and 2^4 are factors of (6)^2 \times x \times (12)^1 \times (3)^6 \times (7)^2, which is the smallest possible value of x?

Problems based on Numbers Test 7

Question : 15 of 18

Marks: +1, -0

If both

17^2

and

2^4

are factors of

(6)^2 × x × (12)^1 × (3)^6 × (7)^2

, which is the smallest possible value of x?

Solution:

6^7 × x × 12^1 × 3^6 × 7^2

= 3^2 × 2^2 × x × 2^2 × 3 ×3^6 × 7^2

Since the number already, containing

2^4

, thepossible smallest value of x is

17^2 = 289

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