Problems based on Numbers Test 6

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Question : 4 of 40

Marks: +1, -0

If

1^3 + 2^3 + … + 9^3 = 2,025

, then the approximate value of

(0.11)^3 + (0.22)^3 + … + (0.99)^3

is:

0.2695
0.3695
2.695
3.695

Solution:

The given expression

1^3 + 2^3 + … + 9^3 = 2,025

The value of

(0.11)^3 + (0.22)^3 + … + (0.99)^3

=(0.11)^3(1^3+2^3+...+9^3)

=(0.11)^3(2025)

= 0.001331 × 2025

= 2.695275 = 2.695

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