Problems based on Numbers Test 5

Let the digit at the unit place be x.
So, the digit at the ten place 15 - x.
The difference between two digits of the two digit numbers = 3
$\mathit{x}-\left(15-\mathit{x}\right)=3$
$\mathit{x}-15+\mathit{x}=3$
$2\mathit{x}=18$
$\mathit{x}=9$
The first number x = 9
Digit at the ten’s place = 15 - 9 = 6
The product of the two digit number = 9 × 6 = 54 (other than those given as options)