Problems based on Numbers Test 4

Question : 1 of 40

Marks: +1, -0

What will be the remainder when

19^10

is divided by 20?

Solution:

The value of

19^101

Unit digit of

9^1=9

9^2=1

9^3=9

So,

19^{101}=19^{2×50}×19^1=19^1

So, the remainder is 1 when 19 is divided by 20.

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