Problems based on Numbers Test 3

Let the number of persons = x.
Total money = Rs 9,000
Money divided equally among persons $=9,\frac{000}{\mathit{x}}$
Number of persons when 20 persons are more = x + 20 persons
Each person gets Rs 160 less
According to the statement,
$\frac{9000}{\mathit{x}}-160=\frac{9000}{\mathit{x}+20}$
$9000\mathit{x}+180000-160{\mathit{x}}^2-3200\mathit{x}=9000\mathit{x}$
${\mathit{x}}^2+45\mathit{x}-25\mathit{x}-1125=0$
$\left(\mathit{x}+45\right)\left(\mathit{x}-25\right)=0$
x + 45 = 0, is rejected because it is negative
x - 25 = 0
x = 25
The number of persons equal to 25.