Problems based on Numbers Test 2

Question : 3 of 40

Marks: +1, -0

The expression

2^{6n} - 4^{2n}

, where, n is a natural number is always divisible by:

Solution:

The given expression

2^{6n} - 4^{2n}

where, n is the natural number
when n = 1

2^{6(1)}-4^{2(1)}=2^6-4^2

64-16=48

when n = 2

2^{6(2)}-4^{2(2)}

= 4,096 - 256

= 3,840

So, it is divisible by 48.

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