Let a, b, c, d, e, f (≠2) be six distinct positive real numbers such that a : b = c : d = e : f = 2 : 3. Then \frac{3e-4}{3f-6} can never be equal to the expression____.

Correct Answer is : 3c+4a+23b+4d+3

Problems based on Numbers Test 1

Question : 2 of 40

Marks: +1, -0

Let a, b, c, d, e, f (≠2) be six distinct positive real numbers such that a : b = c : d = e : f = 2 : 3. Then

{3e-4}/{3f-6}

can never be equal to the expression____.

${3a+4c+2}/{3b+4d+3}$
${2e+7c}/{2f+7d}$
${a+c+4}/{b+d+6}$
${3c+4a+2}/{3b+4d+3}$

Validate

Solution:

Let a, b, c, d, e and f, be six distinct positive real numbers.
a : b = c : d = e : f = 2 : 3

a/b=c/d=e/f=2/3

3a = 2b ......(i)
3c = 2d ......(ii)
3e = 2f ......(iii)
Let a = 4 from (i) b = 6
Let c = 8 from (ii) d = 12
Let e = 16 from (iii) f = 24
The given expression

{3e-4}/{3f-6}

={3(16)-4}/{3(24)-6}

=44/66=4/6=2/3

So, by replacing the values of a, b, c, d, e, f in the given option
The expression below is not equal to

{3c+4a+2}/{3b+4d+3}

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