Problems based on Numbers Test 1

Question : 19 of 40

Marks: +1, -0

If the numerator of a fraction is increased by 2 and the denominator is increased by 3, the fraction becomes

7/ 9

and if both the numerator as well as the denominator are decreased by 1, the fraction becomes

4 /5

. The original fraction is:

Solution:

Let the original fraction

= x/ y

; then

{x+2}/{y+3}=7/9

⇒9x + 18 = 7y + 21

⇒ 9x - 7y = 3

...(i)
Again,

{x-1}/{y-1}=4/5

⇒5x - 5 = 4y - 4

⇒ 5x - 4y = 1

...(ii)
Solving equations (i) and (ii) we get, x = 5 and y = 6
Hence, fraction

=x/y=5/6

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