Probability Practice Test 2

Question : 32 of 37

Marks: +1, -0

A problem is given to three students. The chances of their solving are

1/5,1/3

and

3/ 5

respectively. Then the probability that the problem will be solved is:

Solution:

P(E_1)=1/5,P(E_2)=1/3,P(E_3)=3/5

P(E_1 U E_2 U E_3 )

= 1- P(\ov E_1 ) P(\ov E_2 ) P(\ov E _3)

=1-(1-1/5)(1-1/3)(1-3/5)

=1-4/5 . 2/3 . 2/5

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