Probability Practice Test 2

Outcomes when two dies is tossed twice
sum of die 8 = 5
sum of die 10 = 3
Total chance of outcomes = 36
Probability of sum 8 $=\frac{5}{36}$
Probability of sum 10 $=\frac{3}{36}$
Probability of sum is neither 8 nor 10 is $=1-\left(\frac{3}{36}.\frac{5}{36}\right)$