Probability Practice Test 2

Question : 20 of 37

Marks: +1, -0

Host, his wife and 8 guests are to be seated on a round dining table at random. The probability that the host and his wife sit together is

Solution:

Favourable ways = 2!.8!.
Total ways of arrangement of 10 persons = (10 – 1)! = 9!

∴P={2!8!}/{9!}=2/9

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