Probability Practice Test 1

Question : 32 of 40

Marks: +1, -0

The probabilities of three mutually exclusive events A, B and C are given by

2/3, 1/4 \and 1/6

respectively. The statement

Solution:

Since the events A, B and C are mutually exclusive, we have
P(A ∪ B ∪ C)

=2/3+1/4+1/6=13/12>1

, 1, which is not possible.
Hence, the statement is false.

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