Probability Practice Test 1

P(A ∩ B) = P(A) + P(B) – P(A ∪ B) = 0.4 + 0.3 – 0.7 = 0
∴ P(A ∩ B) ≠ P(A) P(B) so A and B are not independent.
{Since P(A ∩ B) ≠ 1, A and B are not exhaustive.}
P(A ∩ B) = 0 gives A and B are mutually exclusive.